Math, asked by latabhanushali12, 8 months ago

factorise (2a+3b)^3-27c^3

Answers

Answered by shrutisethi200719

0

(2a+3b)³ - 27c³ = (2a+3b-3c)(2a+3b)²+9c²+(2a+3b)(3c) = (2a+3b-3c)(4a²+9b²+9c²+12ab+6ac+9bc)

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