Question

Factorise
(2a-3b) (m+n) + (3a-2b) (m+n)​

Answer 1

Question :- Factorise (2a-3b)(m+n)+(3a-2b)(m+n) by regrouping ?

Solution :-

→ (2a - 3b)(m + n) + (3a - 2b)(m + n)

→ 2am + 2an - 3bm - 3bn + 3am + 3an - 2bm - 2bn

regrouping the likes terms, we get,

→ (2am + 3am) + (2an + 3an) - (3bm + 2bm) - (3bn + 2bn)

→ 5am + 5an - 5bm - 5bn

→ (5am + 5an) - (5bm + 5bn)

→ 5a(m + n) - 5b(m + n)

→ 5(m + n)(a - b) (Ans.)

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