factorise:(2a^5-32a)
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6
Step-by-step explanation:
2a^5-32a
2a(a^4-32)
2a(a^2)^2-(2^3)^2
2a(a^2-2^3)(a^2+2^3)
2a(a^2-8)(a^2+8)
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Answered by
4
Answer:
2a^5-32a
= 2 a (a^4 - 16)
= 2 a [(a^2)^2 - (4)^2]
= 2 a (a^2 - 4)(a^2 + 4)
= 2 a (a^2 - 2^2)(a^2 + 4)
= 2 a (a - 2)(a + 2)(a^2 + 4)
Step-by-step explanation:
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