factorise 2a + 6b -3 (a+3b)^2
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Answered by
252
2(a+3b)-3(a+3b)^2
(a+3b)[2-3(a+3b)]
(a+3b)[2-3a-9b)
(a+3b)[2-3(a+3b)]
(a+3b)[2-3a-9b)
Answered by
181
Answer:
Factors of 2a+6b-3(a+3b)²=
(a+3b)(2-3a-9b)
Explanation:
Factorising 2a+6b-3(a+3b)²
= 2(a+3b)-3(a+3b)(a+3b)
= (a+3b)[2-3(a+3b)]
= (a+3b)(2-3a-9b)
Therefore,
2a+6b-3(a+3b)²
= (a+3b)(2-3a-9b)
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