factorise;
2a^7-128a
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Given: 2a^7 - 128a
Answer: 2a (a + 2)(a - 2)(a2 - 2a + 4)(a2 + 2a + 4)
Step-by-step explanation:
2a (a^6 - 64)
2a [(a^3)^2 - (8)^2]
using formula a^2 - b^2 = (a+b)(a-b)
2a (a^3 + 8)(a^3 - 8)
2a [(a)^3 + (2)^3)][(a)^3 - (2)^3]
using formula a^3 + b^3 = (a + b)(a^2 - ab + b^2)
and a^3 - b^3 = (a - b)(a^2 + ab + b^2)
2a (a + 2)(a^2 - 2a + 4)(a - 2)(a^2 + 2a + 4)
2a (a + 2)(a - 2)(a^2 - 2a + 4)(a^2 + 2a + 4)
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