Question

factorise (2a-b)^2-10a+4b

Answer 1

 By Formula,

$(a-b)^2 = a^2 + b^2 -2ab$
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$(2a-b)^2 -10a + 4b$

$[4a^2 + b^2 -4ab ] -10a + 4b$

$4a^2 + b^2 -4ab -10a + 4b$

$4a^2  -10a + b^2 + 4b -10a -4ab$

2a(2a-5) + b(b+4) -2a(5+ 2b)


i hope this will help you



-by ABHAY