Question

factorise (2a+b)^2-(2a-b)^2​

Answer 1

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

factorise (2a+b)^2-(2a-b)^2

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

╔════════════════════════╗

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _✍️

$= > {(2a + b)}^{2} - {(2a - b)}^{2}$

Here,this identity is used:-

$\bold{\red{= > {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab}}$

$= > {(2a)}^{2} + {b}^{2} + 2(2a)(b) - [{(2a)}^{2} + {b}^{2} - 2(2a)(b)]$

$\huge\mathcal{know}$

• $\bold{+\:-\:=\:-}$
• $\bold{-\:-\:=\:+(but \:signs \:of\: -)}$

$= > 4 {a}^{2} + {b}^{2} + 4ab - 4 {a}^{2} - {b}^{2} + 4ab$

$= > {b}^{2} + 4ab - {b}^{2} + 4ab$

$= > 4ab + 4ab$

$= 8ab$

Hence,answer is 8ab

╚════════════════════════╝

нσρє ıт нєłρs yσυ

_____________________

тнαηkyσυ