Math, asked by pearl1030, 11 months ago

factorise (2a+b)^2+5(2a+b)^2+6​

Answers

Answered by jiyaroy58
4

Answer:

Factorisation of (2a-b)²+2(2a-b)-8

= (2a-b+4)(2a-b-2)

Explanation:

Given (2a-b)²+2(2a-b)-8

To Find:

Factorisation of (2a-b)²+2(2a-b)-8

solution:

Splitting the middle term, we get

= (2a-b)²+4(2a-b)-2(2a-b)-8

= (2a-b)[2a-b+4]-2[2a-b+4]

= (2a-b+4)(2a-b-2)

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Step-by-step explanation:

hope it's helpful to you....

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