factorise (2a+b)^2+5(2a+b)^2+6
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Answer:
Factorisation of (2a-b)²+2(2a-b)-8
= (2a-b+4)(2a-b-2)
Explanation:
Given (2a-b)²+2(2a-b)-8
To Find:
Factorisation of (2a-b)²+2(2a-b)-8
solution:
Splitting the middle term, we get
= (2a-b)²+4(2a-b)-2(2a-b)-8
= (2a-b)[2a-b+4]-2[2a-b+4]
= (2a-b+4)(2a-b-2)
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Step-by-step explanation:
hope it's helpful to you....
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