Math, asked by akshatrai8, 12 hours ago

factorise(2a+b)^2−6a−3b−4​

Answers

Answered by anbukingky
0

Step-by-step explanation:

   (2a+b)^2−6a−3b−4

=(2a+b)^2−3(2a+b)−4

=(2a+b)^2−4(2a+b)+(2a+b)−4

=(2a+b)((2a+b)−4)+1((2a+b)−4)

=(2a+b−4)(2a+b+1)

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