Factorise (2a+b)^2-6a-3b-4
The ans is (2a+b+1)(2a+b-4)
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Answered by
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[0010001111]... Hello User... [1001010101]
Here's your answer...
(2a+b)²-6a-3b-4
= (2a+b)²-3(2a+b)-4
Let 2a+b = x
Then the equation becomes...
x²-3x-4
= x²-4x+x-4
= x(x-4)+1(x-4)
= (x+1)(x-4)
= (2a+b+1)(2a+b-4)
[0110100101]... More questions detected... [010110011110]
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//This is your friendly neighbourhood UnknownDude
Here's your answer...
(2a+b)²-6a-3b-4
= (2a+b)²-3(2a+b)-4
Let 2a+b = x
Then the equation becomes...
x²-3x-4
= x²-4x+x-4
= x(x-4)+1(x-4)
= (x+1)(x-4)
= (2a+b+1)(2a+b-4)
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
Answered by
0
Given Equation is (2a + b)^2 - 6a - 3b - 4.
It can be written as,
⇒ (2a + b)^2 - 3(2a - b) - 4.
⇒ (2a + b)^2 - 4(2a - b) + (2a - b) - 4.
⇒ (2a + b)[2a + b - 4] + 1[2a + b - 4]
⇒ (2a + b + 1)(2a + b - 4).
Hope it helps!
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