Question

Factorise (2a-b)²-9c²​

Answer 1

Answer:

Applying the identities: a

2

−b

2

=(a+b)(a−b) and (a+b)

2

=a

2

+b

2

+2ab

Using the above identities, the equation a

2

+2ab+b

2

−9c

2

can be factorised as follows:

a

2

+2ab+b

2

−9c

2

=(a+b)

2

−9c

2

=(a+b)

2

−(3c)

2

=(a+b+3c)(a+b−3c)

Hence, a

2

+2ab+b

2

−9c

2

=(a+b+3c)(a+b−3c)

Answer 2

Step-by-step explanation:

(2a-b+3c)(2a-b-3c)

hope it helps

thanks