Question

factorise 2a2+4a2b+8a2c
​

Answer 1

Factorization Problem

• Given expression, $2a^{2}+4a^{2}b+8a^{2}c$

• Here we see that each term of the given expression contains $a^{2}$ and so we can take $a^{2}$ common.
• $\to a^{2}\:(2+4b+8c)$

• Since each term inside the first bracket contains $2$ in their factors, we take $2$ common.
• $\to 2a^{2}\:(1+2b+4c)$

Answer.

$\therefore$ the required factorization is

• $\bold{2a^{2}\:(1+2b+4c)}$.

Read more on Brainly.in

1. factorize (X+1)(2x-1)(4x²+3x-1)/(2x²+x-1)(x+1)

- https://brainly.in/question/8241578

2. factorise (x^2+x)^2+4(x^2+x)-12

- https://brainly.in/question/9656698

Answer 2

Answer:

I don't know

Step-by-step explanation:

I don't know=I+don't+know

I=I don't know-dony know