Question

Factorise:- 2a²(b²-c²)+b²(2c²-2a)+2c(a²-b²)​

Answer 1

Answer:

Step-by-step explanation:

Here you go mate

Step 1

2a²(b²-c²)+b²(2c²-2a)+2c(a²-b²)​  Question

Step 2

2a²(b²-c²)+b²(2c²-2a)+2c(a²-b²)​  Factorise

2a^2b^2−2a^2c^2+2b^2c^2+2a^2c-2ab^2-2b^22c

Step 3

2a^2b^2−2a^2c^2+2b^2c^2+2a^2c-2ab^2-2b^22c  Solve

2(a^2b^2−a^2c^2+b^2c^2+a^2c−ab^2−b^2c)

Answer

2(a^2b^2−a^2c^2+b^2c^2+a^2c−ab^2−b^2c)

Hope this helped