Math, asked by santoshsahoo1977, 2 days ago

FACTORISE

2a2(b2 – c2) + b2(2c2 – 2a2) + 2c2(a2 – b2)​

Answers

Answered by NikBeanie
0

Answer:

•Factorise:

(a) 14m5n4p2 - 42m7n3p7 - 70m6n4p3 (b) 2a2(b2 - c2) + b2(2c2 - 2a2) + 2c2(a2 - b2)

•The area of a rectangle is 6a2 + 36a and 36a width.

Find the length of the rectangle.

•What are the common factors of the following terms?

(a) 25x2y, 30xy2 (b) 63m3n, 54mn4

Answered by arwinsidhu7300
7

Answer:

a2 + b2 + c2ab-bc- ca = 0

Multiply both sides with 2, we get

2(a2 + b2 + c2ab-bc-ca) = 0

→ 2a2 + 2b2 +2c2 - 2ab - 2bc - 2ca =

→ a2 + a2 + b2 + b2 + c2 + c2- 2ab -

2bc2ca0

(a2 - 2ab + b2) + (b2-2bc + c2) + (c2

- 2ca + a2) = 0

(a - b)2 + (b − c)2 + (ca)2 = 0

Since the sum of squares is zero, it means each term should be zero.

(a - b)2 = 0, (b − c)2 = 0, (ca)2 = 0

⇒ a - b = 0, b-c= 0, c-a=0

→ a=b, b = c, c = a

⇒a= b = c

Put this value in the equation

a/b+c+b/c+a +c/b+a =3/2

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