Math, asked by baishyamayuri3, 10 days ago

factorise:

2a³+16b³-5a-10b​

Answers

Answered by Anonymous
3

Step-by-step explanation:

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Answered by Anonymous
10

Answer :

  • 2a³ + 16b³ - 5a - 10b = (a + 2b) (2a² - 4ab + 8b² - 5)

Given :

  • 2a³ + 16b³ - 5a - 10b

To find :

  • Factorise

Solution :

》2a³ + 16b³ - 5a - 10b

》2(a³ + 8b³) - 5(a + 2b)

》2(a³ + (2b)³) - 5(a + 2b)

As we know that

  • a³ + b³ = (a + b) (a² - ab + b²)

》2[(a + 2ab) (a² - 2ab + 4b²)] - 5) a + 2b)

》(a + 2b) (2a² - 4ab + 8b² - 5)

Hence, 2a³ + 16b³ - 5a - 10b = (a + 2b) (2a² - 4ab + 8b² - 5)

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