factorise:
2a³+16b³-5a-10b
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Answer :
- 2a³ + 16b³ - 5a - 10b = (a + 2b) (2a² - 4ab + 8b² - 5)
Given :
- 2a³ + 16b³ - 5a - 10b
To find :
- Factorise
Solution :
》2a³ + 16b³ - 5a - 10b
》2(a³ + 8b³) - 5(a + 2b)
》2(a³ + (2b)³) - 5(a + 2b)
As we know that
- a³ + b³ = (a + b) (a² - ab + b²)
》2[(a + 2ab) (a² - 2ab + 4b²)] - 5) a + 2b)
》(a + 2b) (2a² - 4ab + 8b² - 5)
Hence, 2a³ + 16b³ - 5a - 10b = (a + 2b) (2a² - 4ab + 8b² - 5)
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