Question

factorise 2a3-8a2 + За - 12​

Answer 1

Answer:

We think you wrote:

2a3-8a2+3a-12

This deals with simplification or other simple results.

Overview

Steps

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1 solution(s) found

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Step by Step Solution

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Reformatting the input :

Changes made to your input should not affect the solution:

(1): "a2" was replaced by "a^2". 1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

(((2 • (a3)) - 23a2) + 3a) - 12

STEP

2

:

Equation at the end of step

2

:

((2a3 - 23a2) + 3a) - 12

STEP

3

:

Checking for a perfect cube

3.1 2a3-8a2+3a-12 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 2a3-8a2+3a-12

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 3a-12

Group 2: -8a2+2a3

Pull out from each group separately :

Group 1: (a-4) • (3)

Group 2: (a-4) • (2a2)

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Add up the two groups :

(a-4) • (2a2+3)

Which is the desired factorization

Polynomial Roots Calculator :

3.3 Find roots (zeroes) of : F(a) = 2a2+3

Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F(a)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers

Answer 2

Answer:

(2a²+3)(a-4)

Step-by-step explanation:

2a³-8a² +3a-12

=2a²(a-4) +3(a-4)

=(2a²+3)(a-4)

hope it helps :)