Question

factorise (2a³-b³)³-b^9​

Answer 1

Answer:

Now, 2√2 a³ - 3√3 b³

= (√2)³ a³ - (√3)³ b³

= (√2 a)³ - (√3 b)³ [∵ a³b³ = (ab)³]

= (√2 a - √3 b){(√2 a)² + (√2 a × √3 b) + (√3 b)²},

since a³ - b³ = (a - b)(a² + ab + b²)

= (√2 a - √3 b)(2a² + √6 ab + 3b²),

which is the required factorization.

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Answer 2

Step-by-step explanation:

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