factorise 2a⁵- 32q
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Answer:
2a^5 - 32a
• Taking 2a common in both -
2a (a⁴ - 16)
= 2a [(a²)² - (4)²]
• Using identity : a² - b² = (a + b)(a -b)
= 2a [ (a² + 4)(a² - 4) ]
= 2a [ {a² + 4} {(a)² - (2)²}]
• Again using identity : a² - b² = (a + b)(a - b)
= 2a [ {a² + 4} {(a + 2) (a - 2)} ]
= 2a [(a² + 4)(a + 2)(a - 2)]
Step-by-step explanation:
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