factorise 2a7 - 128 a
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Taking common 2a from given expression
factors
2a (a^6-64)
=2a(a^6-2^6)
=2a(a³+2³)(a³-2³)
= 2a(a+2)*(a²-2a+4)*(a-2)
*(a²+2a+4)
required factors
factors
2a (a^6-64)
=2a(a^6-2^6)
=2a(a³+2³)(a³-2³)
= 2a(a+2)*(a²-2a+4)*(a-2)
*(a²+2a+4)
required factors
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