Question

factorise 2ax + bx + 2ay + by​

Answer 1

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1 Method:

Forming a group of first two and the last two terms, we have

(2ax + bx) + (2ay + by)

=> x(2a + b) + y(2a + b)

=> (2a + b) (x + y)

Sometimes grouping can be done in many ways. In the above example we can form the groups of 2ax, 2ay and bx, by.

2 Method:

(2ax + 2ay) + (bx + by)

=> 2a(x + y) + b(x + y)

=> (2a + b) (x + y)

We notice that in whatever way the grouping is done, we will always get the same factors.

Answer 2

Answer:

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Step-by-step explanation:

2ax+bx+2ay+by

=x(2a+b)+y(2a+b)

=(2a+b)(x+y)