Question

Factorise : 2b(2a + b) - 3c(2a + b)

Answer 1

multiply the brackets amd substitute simple

Answer 2

On opening the brackets, we get :

$4 ab \: + 2{b}^{2} - 6ac - 3bc$
Now taking b common from 2b^2 and 3bc and 2a common from 4ab and 3bc

We get,

(2b - 3c) b + 2a (2b - 3c)

0 = (2b - 3c) (b + 2a)

Therefore, the roots are

2b - 3c = 0
(b + 2a) = 0