Question

factorise: 2b²+8ab+4ac+bc give explanation ​

Answer 1

Answer:

(b+4a)(2b+c)

Step-by-step explanation:

$2b {}^{2} + 8ab + 4ac \: + bc \\ = \: 2b(b + 4a) \: + c(4a + b) \\ = (b + 4a)(2b + c)$

No middle term splitting is needed, it is already splited in its factors

Answer 2

Explanation:

2b²+8ab+4ac+bc

=2b (b+4a) + c (b+4a)

=(2b+c) (b+4a)

=(4a+b) (2b+c)