Question

Factorise

2l³ + 432m​

Answer 1

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Answer 2

Answer:

We know that,

a³ + b³ = (a + b) (a² – ab + b²)

2l3 + 432m3 = 2 (l3 + 216m3) [By taking out the common factor 2]

= 2 (l3 + (6m)3)

Here, a = l and b = 6m

Now, substituting in the above formula, we get

2 (l3 + (6m)3) = 2 {(l + 6m) [l2 – l(6m) + (6m)2]}

= 2 (l + 6m) (l2 – 6lm + 36m2)