Question

Factorise (2m+3n)²-(3m+2n)²​

Answer 1

Answer:

2m + 3n)² - (3m + 2n)²

= (2m + 3n + 3m + 2n) [ 2m + 3n - (3m + 2n)]

= (5m + 5n)(-m + n)

= -5(m + n)(m - n)

Answer 2

Step-by-step explanation:

(2m+3n)²-(3m+2n)²

(2m+3n+3m+2n)(2m+3n-3m-2n)

[:.a²-b²=(a+b)(a-b)]

(5m+5n)(-m+n)

5m(-m+n)+5n(-m+n)

-5m²+5mn-5mn+5n²

-5m²+5n²

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