Question

factorise: (2m + 3n)^2 - ( 3m + 2n )^2
please do it step by step and if possible on a piece of paper
thank you!❤​

Answer 1

Answer:

I think the answer is

Step-by-step explanation:

(2m+3n)^2-(3m+2n)^2

=(4m^2+12mn+9n^2) - (9m^2+12mn+4n^2)

=4m^2+12mn+9n^2-9m^2-12mn-4n^2

=-5m^2+5n^2

= -5(m^2 - n^2)