Question

factorise (2m+3n)^2 - (3m+2n)^2 using algebraic identities


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Answer 1

Answer:

Let's simplify step-by-step.

(2m+3n)2−(3m+2n)2

Distribute:

=4m2+12mn+9n2+−9m2+−12mn+−4n2

Combine Like Terms:

=4m2+12mn+9n2+−9m2+−12mn+−4n2

=(4m2+−9m2)+(12mn+−12mn)+(9n2+−4n2)

=−5m2+5n2

Step-by-step explanation:

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Answer 2

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(2m + 3n)² - (3m + 2n)²

= (2m + 3n + 3m + 2n) [ 2m + 3n - (3m + 2n)]

= (5m + 5n)(-m + n)

= -5(m + n)(m - n)

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