Question

Factorise 2mn^2 + 2n^2p + m + 4np + 4mn + p.​

Answer 1

Answer-

(m + p)(2n² + 4n + 1).

Step-by-step explanation-

2mn² + 2n²p + m + 4np + 4mn + p

= (2mn² + 2n²p) + (m + p) + (4np + 4mn)

= 2n²(m + p) + 1(m + p) + 4n(p + m)

= (m + p)(2n² + 1 + 4n)

= (m + p)(2n² + 4n + 1).

Answer 2

Answer:

(m+p) (2n^2+4n+1)

Explanation:

It is grouping of