Question

factorise
2n
${2}$
-32​

Answer 1

2n²-32

=2(n²-16)

=2[(n)²-(4)²]

=2(n-4)(n+4)

please mark my answer as Brainliest please please

Answer 2

hey m8,

{since,$a^{2} -b^{2} = (a-b)(a+b)$}║

$(2n^{2} -32) = 2(n^{2}-16)\\ =2(n-4)(n+4)$