Factorise 2nd part
This question is for 50 points
Attachments:
Answers
Answered by
0
Answer:
(a+b)whole square-2ab
harshita01122004:
but this is identity only
But i want the answer
step by step
(a+b)whole square=a square+b square+2ab.so by shifting we get the answer
sry if its wrong
no problem
you helped me
so
thank you
ok
Answered by
0
Answer:
Step-by-step explanation:
Factorsof1-2ab-(a²+b²)
=(1+a+b)(1-a-b)
Explanation:
Given 1-2ab-(a²+b²)
= 1-2ab-a²-b²
=1-(2ab+a²+b²)
=1-(a+b)²
/*Byalgebraicidentity:x²+y²+2xy=(x+y)²*/
=1²-(a+b)²
=[1+(a+b)][1-(a+b)]
/*Byalgebraicidentity:
x²-y²=(x+y)(x-y)*/
=(1+a+b)(1-a-b)
Therefore,
1-2ab-(a²+b²)=(1+a+b)(1-a-b)
pls mark as brainliest
thank you
No problem
Thank you for your help
most welcome:)
Similar questions