factorise (2p_3) (q+5)
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Answer:
Step-by-step explanation:
16(2p−3q)
2
−4(2p−3q)
=4(2p−3q)[4(2p−3q)−1] take 4(2p-3q) common,
=4(2p−3q)(8p−12q−1)
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