Question

factorise 2t²-t-10 expression which are of the firm ax²+bx+c.
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Answer 1

Step-by-step explanation:

2t²-t-10

=2t²+4t-5t-10

=2t(t+2)-5(t+2)

=(2t-5)(t+2)

2t-5=0 or t+2=0

Therefore, t=5/2 or t=(-2)