Question

factorise ( 2x + 1)square / 3 - (x - 1)square /2​

Answer 1

HELLO Tony

star

Here your answer below,,

$\frac{(2x + 1) {}^{2} }{3} - \frac{(x - 1) {}^{2} }{2} = 0 \\ = > \frac{4x {}^{2} + 4x + 1 }{3} - \frac{x {}^{2} - 2x + 1 }{2} = 0 \\ > \frac{2(4x {}^{2} + 4x + 1) - 3(x {}^{2} - 2x + 1) }{6} = 0 \\ = > 2(4x {}^{2} + 4x + 1) - 3(x {}^{2} - 2x + 1) = 0 \\ = > 8x {}^{2} + 8x + 2 - 3x {}^{2} + 6x - 3 = 0 \\ = > 5x {}^{2} + 14x - 1 = 0 \\ = > 5x {}^{2} + 14x - 1 = 0$

It can't be factories so that it's your answer

I hope that helps you