factorise 2x^2+1\3x-1\3
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Answered by
1
Answer:
Step-by-step explanation:
( 2x + 1/3 )² - ( x - 1/2 )²
= [ ( 2x + 1/3 ) +( x - 1/2 ) ][( 2x + 1/3 ) - ( x - 1/2 )]
= [ 2x + 1/3 + x - 1/2 ][ 2x + 1/3 - x + 1/2 ]
= ( 3x + 1/3 - 1/2 ) ( x + 1/3 + 1/2 )
=[ ( 18x + 2 - 3 )/6 ] [( 6x + 2 + 3 )/6]
= ( 1/36 )( 18x -1 ) ( 6x + 5 )
Answered by
1
Step-by-step explanation:
２x²-３x +１=０
２x²-(２x+１x)+１=０
２x²-２x-x+１=０
２x(x-１)-１(x-１)=０
(２x-１)(x-１)=０
x= １/２ ,１
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