Question

factorise 2x^2-10x-28​

Answer 1

$\huge\boxed{Answer}$

2x² - 10x - 28

2x² - 14x + 4x - 28

2x(x - 7) + 4(x - 7)

(2x + 4) (x - 7)

2(x + 2) (x - 7)

Answer 2

Hello mate.....

given...

$2x {}^{2} - 10x - 28 = 0 \\ \\ 2x {}^{2} - 14x + 4x - 28 = 0 \\ \\ 2x(x - 7) + 4(x - 7) = 0 \\ \\ (2x + 4)(x - 7) = 0 \\ \\ 2x + 4 = 0 \: \: or \: \: x - 7 = 0 \\ \\ 2x = - 4 \: \: or \: \: x = 7 \\ \\ x = - 2 \: or \: 7$

Hope it helps you....♧♧♧