Question

factorise 2x^2 + 11 root 2x + 24

Answer 1

$\textbf{Answer :}$

Now, 2x² + 11√2 x + 24

= 2x² + 8√2 x + 3√2 x + 24

= 2x (x + 4√2) + 3√2 (x + 4√2)

= (x + 4√2) (2x + 3√2),

which is the required factorization.

#$\textbf{MarkAsBrainliest}$

Answer 2

Given,

The polynomial 2x²+11√2 x+24 is given.

To find,

We have to find the factors of the given polynomial.

Solution,

The factors of the given polynomial are (x+3√2/2) and (x+4√2).

We can simply find the factors of the given polynomial by using the quadratic formula.

Firstly, we will calculate the Discriminant 'D'

   D = b² -4ac

   D = (11√2)² - 4(2)(24)

       = 50

Quadratic formula = -b +- √D/2a

                              = -11√2 +- 5√2/4

                              = √2(-11+-5)/4

                             = -3√2/2  ,  -4√2

Hence, the factors of the given polynomial are (x+3√2/2) and (x+4√2).