Math, asked by miles30, 1 year ago

factorise 2x^2 - 14x + 24


rekhaben: 2x^2-14x+24 = x^2-7x+12 = x^2-4x-3x+12 = x(x-4)-3(x-4) = (x-4)(x-3) => x= 4, x=3

Answers

Answered by Anonymous
5
Hola

Answer -

2x^{2} - 14x + 24

 {x}^{2} - 14x + 24 \times 2

 {x}^{2} - 14x + 48


Now we will have to find 2 factors such that their addition is - 14 and if you multiply those factors you will get 48.

=> 2 factors are -8 and -6

as -8 × -6

Therefore,

 {x}^{2} - 8x - 6x + 48


Now we will group in two

thus,


x(x - 8) - 6( x - 8)


So,

Factors =>

(x - 6)(x - 8)

Hope it helps

miles30: thank u so much
Anonymous: Your welcome :)
rekhaben: ur welcome
Answered by liza10987654321
10
= 2x^2 -14x +24
=2x^2 -8x-6x + 24
= 2x(x-4) -6(x-4)
=(2x-6)(x-4)
this is your correct solution...
plz marked as brainliest plzzz

miles30: sorry to say but -8 × -6 = 48. not 24
miles30: but still the last term is 24
miles30: i dont know middle term splitting
miles30: pls teach me
miles30: 8th
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