factorise 2x^2-17xy+26y^2
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Answer : 2x^2 - 4xy - 13xy + 26y^2
common
2x and 13y
2x(x - 2y) - 13y (x - 2y)
common again x - 2y
((x- 2y) 2x - 13y) = 0
now either
x = 2y and x = 13y / 2
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