Question

factorise 2x^2+2√14x+7​

Answer 1

$2x^{2} + 2 \sqrt{14} x + 7$

$2x^{2} + ( \sqrt{14} + \sqrt{14}) x + 7$

$2x ^{2} + \sqrt{14} x + \sqrt{14} x + 7$

$\sqrt{2} x( \sqrt{2} x + \sqrt{7} ) + \sqrt{7}( \sqrt{2} x + \sqrt{7} )$

$( \sqrt{2} x + \sqrt{7} )( \sqrt{2} x + \sqrt{7} )$

Answer 2

${2x}^{2} + \sqrt{14 }x + \sqrt{14} x + 7 \\ = 2x(x + \frac{ \sqrt{14} }{2} ) + \sqrt{14}(x + \frac{ \sqrt{14} }{2} ) \\ = (x + \frac{ \sqrt{14} }{2} ) + (2x + \sqrt{14} )$

Hope it helps..

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