factorise 2x^2-2√2x-3 and find all the zeroes
Answers
Answered by
14
p(x)=2x²-2√2x-3
=2x²+3√2x-√2x-3
=√2x(√2x+3)-1(√2x+3)
=(√2x-1) (√2x+3)
When √2x-1=0
x=1/√2
When √2x+3=0
x=-3/√2
Therefore,zeroes are x=1/√2 and x=-3/√2.
=2x²+3√2x-√2x-3
=√2x(√2x+3)-1(√2x+3)
=(√2x-1) (√2x+3)
When √2x-1=0
x=1/√2
When √2x+3=0
x=-3/√2
Therefore,zeroes are x=1/√2 and x=-3/√2.
Answered by
1
Step-by-step explanation:
Hope the solution is clear to you!
Attachments:
Similar questions