factorise: (2x^2/3 ) - (17x/3) -28
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Solution :
Given ,2x^2/3 - 17x⅓ -28
= 2(x⅓)² - 17x⅓ - 28
Splitting the middle term, we get
= 2(x⅓)² - 4x⅓ - 14x⅓ -28
= x⅓( 2x⅓ - 4 ) - 7( 2x⅓ - 4 )
= ( 2x⅓ - 4 )( x⅓ - 7 )
•••••
Given ,2x^2/3 - 17x⅓ -28
= 2(x⅓)² - 17x⅓ - 28
Splitting the middle term, we get
= 2(x⅓)² - 4x⅓ - 14x⅓ -28
= x⅓( 2x⅓ - 4 ) - 7( 2x⅓ - 4 )
= ( 2x⅓ - 4 )( x⅓ - 7 )
•••••
Answered by
1
I am not sure if this is right or not but yea here-
I hope you understand.
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