Question

factorise: (2x^2/3 ) - (17x/3) -28

Answer 1

Solution :

Given ,2x^2/3 - 17x⅓ -28

= 2(x⅓)² - 17x⅓ - 28

Splitting the middle term, we get

= 2(x⅓)² - 4x⅓ - 14x⅓ -28

= x⅓( 2x⅓ - 4 ) - 7( 2x⅓ - 4 )

= ( 2x⅓ - 4 )( x⅓ - 7 )

•••••

Answer 2

I am not sure if this is right or not but yea here-

I hope you understand.