Question

Factorise 2x^2+3√3x+3

Answer 1

$2x {}^{2} + 3 \sqrt{3} x + 3$

$2x {}^{2} + 2 \sqrt{3} x + \sqrt{3x} + 3$

$2x (x + \sqrt{3} ) + \sqrt{3} (x + \sqrt{3})$


$(2x + \sqrt{3} )(x + \sqrt{3} )$

Regards

Answer 2

The factors of the above quadratic equation are $(x+\sqrt{3})\ \text{and}\ (2x+\sqrt{3})$

Step-by-step explanation:

We need to factorise the following quadratic equation i.e.

$2x^2+3\sqrt{3}x+3$

We can split the middle term of this equation such that,

$2x^2+(2\sqrt{3}+\sqrt3)x+3\\\\=2x^2+2\sqrt{3}x+\sqrt3x+3$

Taking common from above equation such that,

$2x^2+2\sqrt{3}x+\sqrt3x+3\\\\2x(x+\sqrt{3})+\sqrt{3} (x+3)\\\\(x+\sqrt{3})(2x+\sqrt{3})$

So, the factors of the above quadratic equation are $(x+\sqrt{3})\ \text{and}\ (2x+\sqrt{3})$

Learn more,

Factorize

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