Factorise : 2x^2+3√5x+5
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2x² + 3√5x + 5
=> 2x² + 2√5 x+ √5x+5 {< by using splinting method )
=> 2x( x +√5 ) + √5 (x +,√5)
=> (2x +√5)(x+√5) =0
=> x =-√5/2 and x =- √5 Answers ..
hope it helps you !!
₹Rajukumar111
2x² + 3√5x + 5
=> 2x² + 2√5 x+ √5x+5 {< by using splinting method )
=> 2x( x +√5 ) + √5 (x +,√5)
=> (2x +√5)(x+√5) =0
=> x =-√5/2 and x =- √5 Answers ..
hope it helps you !!
₹Rajukumar111
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