Math, asked by kankan12, 1 year ago

factorise: 2x^2+3x-90

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Answered by abdul9838

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$\huge \bf \: hola \\ \\ \bf \: hey \: user \: here \: is \: ans \\ \\ \bf \huge \: solution \\ \\ \bf \: 2 {x}^{2} + 3x - 90 = 0 \\ \\ \bf \: 2 {x}^{2} + (15 - 12)x - 90 = 0 \\ \\ \bf \: 2 {x}^{2} + 15x - 12x - 90 = 0 \\ \\ \bf \: x(2x + 15) - 6(2x + 15) = 0 \\ \\ \bf \: (x - 6)(2x + 15) = 0 \\ \\ \bf \: x = 6 \\ \\ \bf \: and \\ \\ \bf \: x = - \frac{15}{2}$

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Answered by subham9961

2x^2+3x-90

=2x^2+(15-12)x-90

=2x^2+15x-12x-90

=2x^2-12x+15x-90

=2x(x-6)+15(x-6)

=(x-6)(2x+15)Answer

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factorise: 2x^2+3x-90