factorise 2x^2+4x^3+2x+1.
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Answer:
4x^3+2x^2+2x+1
we observed that put the value of x is zero
4.(-1/2)^3+2.(-1/2)^2+2.(-1/2)+1
=4.-1/8+2.1/4+2.-1/2+1
=-1/2+1/2-1+1
=0
Hence
x=-1/2
=> 2x+1=0
= 4x^3+2x^2+2x+1 ➗ 2x+
(2x+1)(2x^2+1) Answer
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