Question

Factorise 2x^2 + 5/6x + 1/12

Answer 1

2x^2 + 5/6 x + 1/ 12 
taking l.c.m as 12 we gety 
24x^2 + 10x + 1 = 0 
{(24x +12) ( 24x - 2) }/24 
{12 ( 2x +1) 2 ( 12x -1) }/24 
(2x +1) ((12x -1)  is the factors of the above problem

Answer 2

Answer:

The required factors of the equation are : (6x + 1) and (4x + 1)

Step-by-step explanation:

The equation which is to be factorized is given to be :

2x² + 5/6x + 1/12 = 0

First multiplying each term of the equation by 12

⇒ 24x² + 10x + 1 = 0

Now, factorize the above equation formed.

⇒ 24x² + 6x + 4x + 1 = 0

⇒ 6x(4x + 1) + 1(4x + 1) = 0

⇒ (6x + 1)·(4x + 1) = 0

⇒ x = -1/6 or x = -1/4

Thus, The required factors of the equation are : (6x + 1) and (4x + 1)