Factorise 2x^2+5root3x+6
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Answered by
14
Hey mate!
Here is yr answer....
___________________________
= 2x² + 5√3x +6
= 2x² + 4√3x + √3x + 6
= 2x(x+2√3) + √3(x+2√3)
= (2x+√3) (x+2√3)
Therefore, the factors are (2x+√3) and (x+2√3)
Hope it helps...
Here is yr answer....
___________________________
= 2x² + 5√3x +6
= 2x² + 4√3x + √3x + 6
= 2x(x+2√3) + √3(x+2√3)
= (2x+√3) (x+2√3)
Therefore, the factors are (2x+√3) and (x+2√3)
Hope it helps...
JaishikaKumawat:
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Answered by
18
⭐Solution ⭐
2x² + 5√3x + 6
=> 2x² + 4√3x + √3x + 6
=> 2x(x + 2√3) + √3(x + 2√3)
=> (2x + √3)(x + 2√3)
Hence,
(2x + √3) and (x + 2√3) are the factors of this identity.
2x² + 5√3x + 6
=> 2x² + 4√3x + √3x + 6
=> 2x(x + 2√3) + √3(x + 2√3)
=> (2x + √3)(x + 2√3)
Hence,
(2x + √3) and (x + 2√3) are the factors of this identity.
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