Factorise:2x^2+6y^2+8z^2-2√2xy+4√2yz-8xz
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Answer: The answer is (-\sqrt2x+y+2\sqrt2z)(-\sqrt2x+y+2\sqrt2z).)
Step-by-step explanation: We are given to factorise the following expression:
E=2x^2+y^2+8z^2-2\sqrt2xy+4\sqrt 2yz-8xz.
We will be using the following factorisation formula:
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca.
We have
E=2x^2+y^2+8z^2-2\sqrt2xy+4\sqrt 2yz-8xz=(-sqrt2x)^2+y^2+(2\sqrt2z)^2+2(-\sqrt2x)y+2y(2\sqrt2z)+2(2\sqrt2z)(-\sqrt2x)=(-\sqrt2x+y+2\sqrt2z)^2=(-\sqrt2x+y+2\sqrt2z)(-\sqrt2x+y+2\sqrt2z).
Thus, the answer is (-\sqrt2x+y+2\sqrt2z)(-\sqrt2x+y+2\sqrt2z).
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