Factorise 2x^2 - 7x - 15
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Answered by
7
2x^2-7x-15
⇒2x^2-10x+3x-15=0 (Factors)
⇒2x(x-5)+3(x-5)=0 (Taking 2x as common in first two terms and 3 as comon in next two terms)
⇒(2x+3)(x-5)=0 (Take x-5as common)
⇒2x^2-10x+3x-15=0 (Factors)
⇒2x(x-5)+3(x-5)=0 (Taking 2x as common in first two terms and 3 as comon in next two terms)
⇒(2x+3)(x-5)=0 (Take x-5as common)
Answered by
23
2x² - 7x - 15
=> 2x² - 10x + 3x - 15
=> 2x(x-5) + 3(x-5)
=> (x-5)(2x+3)
=> 2x² - 10x + 3x - 15
=> 2x(x-5) + 3(x-5)
=> (x-5)(2x+3)
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