Question

Factorise 2x^2 +7x -4​

Answer 1

$2 {x}^{2} + 7x - 4 \\ 2 {x}^{2} + 8x - x - 4 \\ 2x(x + 4) - 1(x + 4) \\ (2x - 1)(x + 4)$

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Answer 2

Answer:

(2−1)(+4)

Step-by-step explanation:

22+7−4

1. Use the sum-product pattern

22+7−4

22+8−−4

2. Common factor from the two pairs

22+8−−4

2(+4)−1(+4)

3. Rewrite in factored form

2(+4)−1(+4)

(2−1)(+4)

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