Factorise 2x 2 + 7x + 5√2 = 0 by completing the following activity Solution: 2x 2 + 7x + 5√2 = 0 ∴ 2x 2 + 5x + 2x + 5√2 = 0 ∴ x(√2x + 5) + √2 _____= 0 ∴ _____ (x + √2) = 0 ∴ _____ = 0 or x + √2 = 0 ∴ x = _____ or x = − √2 ∴ The roots of the given quadratic equation are _____ and −√2.
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Answer:
\[\\sqrt{2}x^2 + 7x + 5\sqrt{2}=0\]
\[\sqrt{2}x^2 + 5x + 2x + 5\sqrt{2} = 0\]
\[x\left( \sqrt{2}x+ 5 \right) + \sqrt{2}\left( \sqrt{2}x+ 5 \right) = 0\]
\[\left( \sqrt{2}x + 5 \right)\left( x + \sqrt{2}
\right) = 0\]
\[\left( \sqrt{2}x+ 5 \right) = 0 \text{ or} \left(
x + \sqrt{2} \right) = 0\]
\[\therefore x = \frac{- 5}{\sqrt{2}} \text{ or } x
=- \sqrt{2}\]
\[\therefore \frac{- 5}{\sqrt{2}} \text{ and } - \sqrt{2} \text{ are the roots of the equation }.\]
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√2x² +7x+5√/2=0
√2x² + 5x + 2x +5√2=0
(√2x + 5) + √2 (√2x+5) = 0
√√2x+5) (x + √2) = 0
(√2x+5) = 0 or (x + √2) = 0
-5 or x = -√2
-5 √2 and -√2 are the roots of the equation
I MIGHT ME WRONG BUT IF U GET THE ANSWER LET ME KNOW
√2x² + 5x + 2x +5√2=0
(√2x + 5) + √2 (√2x+5) = 0
√√2x+5) (x + √2) = 0
(√2x+5) = 0 or (x + √2) = 0
-5 or x = -√2
-5 √2 and -√2 are the roots of the equation
I MIGHT ME WRONG BUT IF U GET THE ANSWER LET ME KNOW
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